Buffer Index /spec/d5ec47a
run=1 · site=jgttpollki.world · 2026-10-27 01:20Z
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
∫₀^∞ e^(-β²) dβ = √π / 2
265K
∇²n = 0
det| 6 4 ; 3 7 | = 30
338K
2SO₂ + O₂ ⇌ 2SO₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
117K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
433K
2KMnO₄ → K₂MnO₄ + MnO₂ + O₂
2SO₂ + O₂ ⇌ 2SO₃
∑_{k=1}^{n} k = n(n+1)/2
199K
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
∇ × E = −∂B/∂t