Buffer Index /spec/d5ec47a
run=1 · site=jgttpollki.world · 2026-10-27 01:04Z
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
∇²n = 0
∑_{k=1}^{n} k = n(n+1)/2
338K
2SO₂ + O₂ ⇌ 2SO₃
BaCl₂ + Na₂SO₄ → BaSO₄↓ + 2NaCl
117K
2KMnO₄ → K₂MnO₄ + MnO₂ + O₂
2SO₂ + O₂ ⇌ 2SO₃
∫₀^∞ e^(-t²) dt = √π / 2
199K
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
431K
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
det| 12 9 ; 0 13 | = 156
∇ × E = −∂B/∂t
λ = h/p