Buffer Index /spec/d5ec47a
run=1 · site=jgttpollki.world · 2026-10-26 22:29Z
∇²x = 0
det| 10 6 ; 6 11 | = 74
354K
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
E = mc²
∫₀^∞ e^(-z²) dz = √π / 2
344K
det| 9 3 ; 4 10 | = 78
4Fe + 3O₂ → 2Fe₂O₃
∑_{k=1}^{n} k = n(n+1)/2
E = mc²
4Fe + 3O₂ → 2Fe₂O₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O