Buffer Index /spec/d5ec47a
run=1 · site=jgttpollki.world · 2026-10-26 22:05Z
∇²x = 0
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
393K
det| 9 3 ; 4 10 | = 78
∑_{k=1}^{n} k = n(n+1)/2
121K
4Fe + 3O₂ → 2Fe₂O₃
∑_{k=1}^{n} k = n(n+1)/2
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
408K
4Fe + 3O₂ → 2Fe₂O₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O