Buffer Index /spec/d5ec47a
run=1 · site=jgttpollki.world · 2026-10-27 01:06Z
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
∇²n = 0
∫₀^∞ e^(-α²) dα = √π / 2
338K
2SO₂ + O₂ ⇌ 2SO₃
SiO₂ + 2C → Si + 2CO
433K
2KMnO₄ → K₂MnO₄ + MnO₂ + O₂
2SO₂ + O₂ ⇌ 2SO₃
det| 5 1 ; 7 6 | = 23
199K
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
∇ × E = −∂B/∂t