Buffer Index /spec/d5ec47a
run=1 · site=jgttpollki.world · 2026-10-27 01:37Z
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
∇²n = 0
∑_{k=1}^{n} k = n(n+1)/2
338K
2SO₂ + O₂ ⇌ 2SO₃
2KMnO₄ → K₂MnO₄ + MnO₂ + O₂
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
186K
2SO₂ + O₂ ⇌ 2SO₃
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
∫₀^∞ e^(-β²) dβ = √π / 2
58K
det| 12 9 ; 0 13 | = 156
∇ × E = −∂B/∂t
λ = h/p