Buffer Index /spec/d5ec47a
run=1 · site=jgttpollki.world · 2026-10-26 22:08Z
∇²x = 0
∫₀^∞ e^(-α²) dα = √π / 2
101K
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
E = mc²
det| 9 3 ; 4 10 | = 78
det| 9 2 ; 1 10 | = 88
332K
4Fe + 3O₂ → 2Fe₂O₃
det| 11 1 ; 1 12 | = 131
295K
∑_{k=1}^{n} k = n(n+1)/2
E = mc²
4Fe + 3O₂ → 2Fe₂O₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O