Buffer Index /spec/d5ec47a
run=1 · site=jgttpollki.world · 2026-10-26 22:22Z
∇²x = 0
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
E = mc²
det| 9 3 ; 4 10 | = 78
det| 12 7 ; 0 13 | = 156
332K
4Fe + 3O₂ → 2Fe₂O₃
det| 6 5 ; 7 7 | = 7
∑_{k=1}^{n} k = n(n+1)/2
E = mc²
4Fe + 3O₂ → 2Fe₂O₃