Buffer Index /spec/d5ec47a
run=1 · site=jgttpollki.world · 2026-10-26 23:31Z
∑_{k=1}^{n} k = n(n+1)/2
2KMnO₄ → K₂MnO₄ + MnO₂ + O₂
∫₀^∞ e^(-z²) dz = √π / 2
131K
CO₂ + H₂O ⇌ H₂CO₃
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
det| 1 4 ; 0 2 | = 2
d/dγ [γ^11] = 11γ^10