Buffer Index /spec/d5ec47a
run=1 · site=jgttpollki.world · 2026-10-26 02:28Z
λ = h/p
det| 11 1 ; 1 12 | = 131
101K
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
C₂H₄ + H₂O → C₂H₅OH
∫₀^∞ e^(-α²) dα = √π / 2
344K
4Fe + 3O₂ → 2Fe₂O₃
det| 3 5 ; 4 4 | = -8
332K
det| 10 6 ; 6 11 | = 74
121K
det| 9 7 ; 1 10 | = 83